Image position and height The geome

Image position and height The geometric model of Figure 17-6 demonstrates
why the distances are the same. Two rays from point O at the tip of
the candle strike the mirror at point P1 and point P2, respectively. Both rays
are reflected according to the law of reflection. The reflected rays are
extended behind the mirror as sight lines, converging at point I, which is
the image of point O. Ray 1, which strikes the mirror at an angle of incidence
of 0°, is reflected back on itself, so the sight line is at 90° to the mirror,
just as ray 1. Ray 2 is also reflected at an angle equal to the angle of
incidence, so the sight line is at the same angle to the mirror as ray 2.
This geometric model reveals that line segments O

P 
1

and I

P 
1

are corresponding
sides of two congruent triangles, OP1P2 and IP1P2. The position
of the object with respect to the mirror, or the object position, do, has
a length equal to the length of O

P 
1

. The apparent position of the image
with respect to the mirror, or the image position, di, has a length equal to
the length of I

P 
1

. Using the convention that image position is negative to
indicate that the image is virtual, the following is true.
You can draw rays from the object to the mirror to determine the size of
the image. The sight lines of two rays originating from the bottom of the
candle in Figure 17-6 will converge at the bottom of the image. Using
the law of reflection and congruent-triangle geometry, the following is true
of the object height, ho, and image height, hi, and any other dimension of
the object and image.
Plane-Mirror Image Height hi
ho
With a plane mirror, image height is equal to object height.
Plane-Mirror Image Position di
do
With a plane mirror, the image position is equal to the negative of the object
position. The negative sign indicates that the image is virtual.

Hasil (Bahasa Indonesia) 1:

Posisi gambar dan tinggi model geometris dari gambar 17-6 menunjukkanMengapa jarak yang sama. Dua sinar dari O titik di ujunglilin menyerang cermin di titik P1 dan titik P2, masing-masing. Kedua ikan paritercermin sesuai dengan hukum refleksi. Pantulan sinardiperpanjang di belakang cermin sebagai garis pandang, konvergen pada titik saya, yanggambar dari titik O. Ray 1, yang menyerang cermin sudut datang0 °, tercermin kembali pada dirinya sendiri, sehingga garis mata adalah pada 90° ke cermin,sama seperti sinar 1. Ray 2 juga tercermin di sudut sama dengan sudutinsiden, sehingga garis terlihat di sudut yang sama ke cermin sebagai ray 2.Ini model geometris mengungkapkan bahwa garis segmen OP 1dan sayaP 1berhubungansisi dua segitiga kongruen, OP1P2 dan IP1P2. Posisiobjek pada cermin, atau posisi objek,, telahpanjang setara dengan panjang OP 1. Posisi yang jelas gambarsehubungan dengan cermin, atau posisi gambar, di, memiliki panjang yang samapanjang sayaP 1. Menggunakan konvensi yang posisi gambar negatif untukmenunjukkan bahwa gambar virtual, berikut ini benar.Anda dapat menarik sinar dari objek untuk cermin untuk menentukan ukurangambar. Garis mata dua sinar yang berasal dari bagian bawahlilin dalam gambar 17-6 akan berkumpul di bagian bawah gambar. Menggunakanthe law of reflection and congruent-triangle geometry, the following is trueof the object height, ho, and image height, hi, and any other dimension ofthe object and image.Plane-Mirror Image Height hi
hoWith a plane mirror, image height is equal to object height.Plane-Mirror Image Position di
doWith a plane mirror, the image position is equal to the negative of the objectposition. The negative sign indicates that the image is virtual.